A bowling ball of mass 5.8 kg moves in a

straight line at 1.59 m/s.

How fast must a Ping-Pong ball of mass

1.528 g move in a straight line so that the two

balls have the same momentum?

Answer in units of m/s.

Velocity of the ping pong ball must be = V2 = 6,035.34m/s

Explanation:

M1 = momentum of the bowling ball

m1 = mass of the bowling ball = 5.8kg

v1 = velocity of the bowling ball = 1.59m/s

M2 = momentum of the ping pong ball

m2 = mass of the ping pong ball = 1.528 g/1000 = 0.001528kg

v2 = velocity of the ping pong ball

Momentum of the bowling ball = M1 = m1v1 = 5.8 * 1.59 = 9.222 kg-m/s

Momentum of the ping pong ball = M2 = M1 = m2v2

= 0.001528 * v2 = 9.222

v2 = 9.222/0.001528 = 6,035.34 m/s