Find the moment of inertia Ix of particle a with respect to the x axis (that is, if the x axis is the axis of rotation), the moment of inertia Iy of particle a with respect to the y axis, and the moment of inertia Iz of particle a with respect to the z axis (the axis that passes through the origin perpendicular to both the x and y axes). Express your answers in terms of m and r separated by commas. Ix, Iy, Iz =

Ix, Iy, Iz = mr²,9mr²,10mr²

Explanation:

The Question has some missing details.

To solve this question, I'll make the following assumptions.

Distance of particle x = r

Distance of particle y = 3r

Given

The mass of each particles = m

The moment of inertia is calculated by adding product of mass" of each particle with the "square of its distance from the axis of the rotation".

Ix = m * (r) ² = mr²

Iy = m (3r) ² = m * 9r² = 9mr²

The distance of z from the axis is r² + (3r) ²

So, Iz = m (r² + (3r) ²)

Iz = m (r² + 9r²)

Iz = m (10r²)

Iz = 10mr²

So, we have

Ix, Iy, Iz = mr²,9mr²,10mr²