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20 October, 03:34

A water jet that leaves a nozzle at 60 m/s at a flow rate of 120 kg/s is to be used to generate power by striking the buckets located on the perimeter of a wheel. Determine the power generation potential of this water jet.

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  1. 20 October, 05:30
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    216000 W or 216 kW

    Explanation:

    Power: This can be defined as the rate at which energy is consumed or used, The S. I unit of power is Watt (W)

    Generally,

    Power = Energy/time

    P = E/t ... Equation 1.

    But

    E = 1/2mv² ... Equation 2

    Where m = mass, v = velocity.

    Substitute equation 2 into equation 1

    P = 1/2mv²/t ... Equation 3

    Let flow rate (Q) = m/t

    Q = m/t ... Equation 4

    Substitute equation 4 into equation 3

    P = Qv²/2 ... Equation 5

    Where Q = flow rate, v = velocity, P = power.

    Given: Q = 120 kg/s, v = 60 m/s

    Substitute into equation 5

    P = 120 (60) ²/2

    P = 60 (60) ²

    P = 60*3600

    P = 216000 W.

    Thus the power generation potential of the water jet = 216000 W or 216 kW
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