Ask Question
19 August, 19:48

A child sitting 1.90 m from the center of a merry-go-round moves with a speed of 2.05 m/s. Calculate the centripetal acceleration of the child. Calculate the net horizontal force exerted on the child. (mass = 28.5 kg).

+4
Answers (1)
  1. 19 August, 21:00
    0
    Acceleration = 2.21m/s^2

    Force = 62.99N

    Explanation:

    Centripetal acceleration = v^2 / r

    Given velocity v = 2.05m/s

    Radius r = 1.90m

    Centripetal acceleration = (2.05) ^2 / 1.90

    2.05 x 2.05 / 1.90

    4.2025/1.90

    2.21m/s^2

    Now, since a = 2.21 m/s^2

    And mass m = 28.5kg

    Force exerted on the child = mass x centripetal acceleration

    That's 28.5kg x 2.21m/s^2

    62.99N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A child sitting 1.90 m from the center of a merry-go-round moves with a speed of 2.05 m/s. Calculate the centripetal acceleration of the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers