A circular room has a radius of 3.0 m. An 80 kg man stands with his back against the wall. The room then spins so the man is moving in a circle. How fast does the man have to be moving so that the normal force from the wall on his back is equal to his weight

Question

Physics

Tiara Bush

11 May, 18:06

A circular room has a radius of 3.0 m. An 80 kg man stands with his back against the wall. The room then spins so the man is moving in a circle. How fast does the man have to be moving so that the normal force from the wall on his back is equal to his weight

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Answers (1)

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Guadalupe Mccoy · Answer 1

Given:

Mass, M = 80 kg

Acceleration due to gravity, g = 9.81 m/s^2

Radius, R = 3 m

Normal force, N = M * a

= M * v/t

Centripetal force, Fc = M * v^2/R

Fc = N

a = v^2/R

v = sqrt (9.81 * 3)

= 5.425 m/s

v = w * R

w = angular velocity

w = 5.425/3

= 1.808 rad/s