An empty capacitor is connected to a 12.0 V battery and charged up. The capacitor is then disconnected from the battery, and a slab of dielectric material (dielectric constant "k" = 2.8) is inserted between the plates. Find the amount by which the potential difference accross the plates changes. Specify whether the change is an increace or a decreace.

Question

Physics

Robbins

10 February, 16:55

An empty capacitor is connected to a 12.0 V battery and charged up. The capacitor is then disconnected from the battery, and a slab of dielectric material (dielectric constant "k" = 2.8) is inserted between the plates. Find the amount by which the potential difference accross the plates changes. Specify whether the change is an increace or a decreace.

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Zachery Kidd · Answer 1

7.71 V

Explanation:

When the charge remains constant, the potential difference decrease by the factor of the dielectric constant K

V new = V initial / K = 12 V / 2.8 = 4.29 V

ΔV (change in potential) = V initial - V new (after dielectric has been added) = 12 V - 4.29 V = 7.71 V

The potential difference decreases by 7.71 V