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22 June, 20:16

The electrons in a particle beam each have a kinetic energy K. What is the magnitude of the electric field that will stop these electrons in a distance d?

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  1. 22 June, 20:47
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    Electric field magnitude

    E = K/qd

    Where

    K = kinetic energy of electron

    d = electron distance

    q = charge

    Explanation:

    Given the relationship between workdone and energy

    Work-energy theorem:

    Net workdone = Energy change

    W = ∆E

    In this case

    W = ∆K. E

    And,

    ∆K. E = K (final) - K (initial)

    To stop the kinetic energy | K (final) = 0

    K (initial) = K (given)

    ∆K. E = 0 - K = - K

    Let the electric force on the electron has magnitude F.

    And

    W = - Fd = ∆K. E = - K

    -Fd = - K

    F = K/d ... 1

    The magnitude of the electric field E that can stop these electron in a distance d:

    E = F/q ... 2

    Where q is the charge on electron.

    substituting equation 1 to 2

    E = (K/d) / q = K/qd

    E = K/qd
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