If a space ship is traveling with a constant acceleration of 75 m/s^2 and travels for three weeks, how far did it travel and what was it's velocity before it stopped?

The final velocity of the ship is, v = 136050000 m/s

The total distance covered, s = 6.94 x 10¹⁷ m

Explanation:

Given data,

The constant acceleration of the space ship, a = 75 m/s²

The time period of the space ship acceleration is t = 3 weeks

t = 1.814 x 10⁶ s

The initial velocity of the ship is u = 0 m/s

The final velocity of the ship is,

v = u + at

= 0 + 75 (1.814 x 10⁶)

= 136050000 m/s

The distance space ship traveled, can be calculated from the second equation of motion.

s = ut + ½ at²

= 0 + ½ 75 (136050000) ²

= 6.94 x 10¹⁷ m

Hence, the total distance covered, s = 6.94 x 10¹⁷ m