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13 August, 17:37

A conveyor belt at a quarry lifts 1,800 kg of sand per minute up a vertical distance of 9.5 meters. The sand is initially at rest, then moves at a speed of 0.28 m/s along the conveyor belt. What is the instantaneous power generated by this machine?

2.8 kW

1.0 kW

3.9 kW

890 W

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Answers (1)
  1. 13 August, 19:02
    0
    The power of the quarry belt is, P = 2.8 kW

    Explanation:

    Given data,

    The mass of the sand, m = 1800 kg

    The displacement of the quarry belt, s = 9.5 m

    The initial velocity of the sand, u = 0

    The final velocity of the sand, v = 0.28 m/s

    The acceleration of the belt, a = (v-u) / t

    = 0.28/10

    = 0.028 m/s²

    The net force acting on the quarry belt is,

    F = mg + ma

    = m (g + a)

    = 1800 (9.8 + 0.028)

    = 17690 N

    The work done by the quarry belt,

    W = F S

    = 17690 x 9.5

    = 168058 N

    The power of the quarry belt,

    P = W / t

    = 168058 / 60

    = 2800 W

    = 2.8 kW

    Hence, the power of the quarry belt is, P = 2.8 kW
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