A 4-A current is maintained in a simple circuit with a total resistance of 2 Ω. How much energy is dissipated in 3 seconds?

A) 3 J

B) 6 J

C) 12 J

D) 24 J

E) 96 J

Answer: Energy dissipated E = 96J

Explanation:

Given:

Current I = 4A

Resistance R = 2 Ohms

Time t = 3 seconds

The energy dissipation in an electric circuit can be derived from the equation below:

E = IVt ... 1

Where;

I = current, V = Voltage (potential difference), t = time and E = energy dissipated

But we know that;

V = I*R ... 2

Substituting equation 2 to 1, we have

E = IVt = I (I*R) t = I^2 (Rt)

Substituting the values of I, R and t

E = 4^2 * 2 * 3 = 96J

Energy dissipated E = 96J