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8 April, 13:56

A block slides down a frictionless inclined ramp. If the ramp angle is 12° and its length is 10 m, find the speed of the block as it reaches the bottom of the ramp, assuming it started sliding from rest at the top.

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  1. 8 April, 14:25
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    v = 6.44 m/s

    Explanation:

    Given that

    L = 10 m

    θ = 12°

    The block slides due to gravitational force.

    The gravitational force along the incline ramp = m g sinθ

    Lets take a is the acceleration of the block along the ramp

    m a = m g sinθ

    a = g sinθ

    The equation of motion along the incline plane

    Lets take final speed = v m/s

    Initial speed u = 0 m/s

    v² = v² + 2 a L

    v² = 2 x g sinθ x L

    v² = 2 x 10 x sin12° x 10 (take g = 10 m/s²)

    v² = 41.58

    v = 6.44 m/s
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