Ask Question
21 August, 01:58

It takes 100,832 J of work to lift an elevator 18.3 meters. If this is done in 21.0 seconds, what is the average power of the elevator during the process?

+3
Answers (1)
  1. 21 August, 04:02
    0
    P=4801.5

    Explanation:

    Given:

    work done = W = 100,832 J

    time = 21.0 sec

    Find:

    P = ?

    Formula:

    P = W/t

    Solution:

    P = W/t

    P = 100,832/21.0

    = 4801.52 J/s or Watts
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “It takes 100,832 J of work to lift an elevator 18.3 meters. If this is done in 21.0 seconds, what is the average power of the elevator ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers