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3 June, 16:09

A cyclist rides 8.0 km east for 20 minutes, then he turns and heads west for 8 minutes and 3.2 km. Finally he rides east for 16 km, which takes 40 minutes. (a) What is the final displacement of the cyclist? (b) What is his average velocity?

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  1. 3 June, 16:42
    0
    a) 20,8 km b) 18,353 km/h

    Explanation:

    We first differentiate between speed and velocity, since the later is a vector, that is besides having a value associated as speed, the direction is also a part of its meaning. Then we assume here that moving towards east is a positive direction, then the total displacement is calculated as (8km - 3.2km + 16km) = 20.8 km. Now for the average speed it is total displacement over total time used. The total time is 68 minutes that in hour is 17/15 hrs=1,1333 hrs. Then the average velocity is 20,8 km / 1,1333 hrs = 18,353 km/hrs
  2. 3 June, 16:47
    0
    Displacement: 20,8 to the east.

    Average velocity: 18,35 km/hour

    Explanation:

    In order to solve this you first have to calculate the total displacement that the cyclist rode, in this case we will use east as positive distance and west as negative:

    +8 km - 3,2 km + 16 km = 20,8

    Now the average velocity is the result of the displacement by the total time it took:

    20,8*60/68 = 18,35 km/hr

    Now we know that the average belocity would be 18,35 kilometer per hour.
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