A 5.0-kg cannonball is fired over level ground with a velocity of 2.00 ⨯ 102 m/s at an angle of 25° above the horizontal. Just before it hits the ground its speed is 150 m/s. Over the entire trip, find the change in the thermal energy of the cannonball and air.

E=147898.01J

Explanation:

A 5.0-kg cannonball is fired over level ground with a velocity of 2.00 ⨯ 102 m/s at an angle of 25° above the horizontal. Just before it hits the ground its speed is 150 m/s. Over the entire trip, find the change in the thermal energy of the cannonball and air

firstly, we look for the time of flight it takes to make the projectile path

T=2Usin∅/g

take g = 9.81m/s

T=2*200sin25 / (9.81)

T=17.23Secs

energy is force * distance

E=f*d

f=m*g

f=5*9.81

f=49.05N

s=distance

s = (v+u) T/2

s = (150+200) 17.23/2

s=3015.25m

49.05N*3015.25m

E=147898.01J