Ask Question
1 January, 18:54

By simultaneously conserving energy and momentum, calculate the energy of the neutron emitted in the forward direction by a beam of 150 keV deuterons undergoing the D-T reaction in a tritium target.

+3
Answers (1)
  1. 1 January, 19:24
    0
    Answer: 2372Kev

    Eg = 2222keV

    Eex = ?

    Eex - Eg = 150keV

    Eex - 2222 = 150

    Eex = 150 + 2222

    Eex = 2372keV

    Explanation:

    The energy possessed by the deuterium particles in their ground state or unexcited state is Eg and in that in their excited state is Eex
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “By simultaneously conserving energy and momentum, calculate the energy of the neutron emitted in the forward direction by a beam of 150 keV ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers