A stack of books rests on a level frictionless surface. A force F acts on the stack, and it accelerates at 3.0 m/s2. A 1.0 kg book is then added to the stack. The same force is applied, and now the stack accelerates at 2.0 m/s2.

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Physics

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30 May, 05:22

A stack of books rests on a level frictionless surface. A force F acts on the stack, and it accelerates at 3.0 m/s2. A 1.0 kg book is then added to the stack. The same force is applied, and now the stack accelerates at 2.0 m/s2.

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Answers (1)

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Emery Morris · Answer 1

m1 = 2 kg

m2 = 3kg

Explanation:

The force can be getting by

F = m * a

F1 = F2

a1 = 3.0 m/s^2

a2 = 2.0 m/s^2

The force F1=F2 because the force is applied so get the a2 acceleration

m1 * a1 = m2 * a2

m2 = m1 + 1kg

m1 * (3.0 m/s^2) = m2 * (2.0 m/s^2)

m1 * (3.0 m/s^2) = (m1 + 1kg) * (2.0 m/s^2)

m1 * (3.0m/s^2-2.0m/s^2) = 2 kg*m/s^2

Solve to find the mass

m1 m/s^2 = 2 kg*m/s^2

m1 = 2 kg

m2 = 3kg