2 In a hydraulic press a force of 20 N is applied to a piston of

area 0.20 m2. The area of the other piston is 2.0 m2. What is

a the pressure transmitted through the liquid,

b the force on the other piston?

Let index 1 refer to the pisyon with smaller section. And index 2, to the other piston.

F1=20N

S1=0.2m²

S2=2m².

a) pressure p = F1/S1=F2/S2.

We get: p=F1/S1=20N/0.2m²=100N/m²

b) force on the other piston:

F2=p*S2

F2=100N/m²*2m²=200N

Answer: p=100N/m², F2=200N