Ask Question
30 June, 22:14

A horizontal jet of water is made to hit a vertical wall with a negligible rebound. If the speed of water from the jet is 'v', the diameter of the jet is 'd' and the density of water is 'p', then what is the force exerted on the wall by the jet of water?

+4
Answers (1)
  1. 1 July, 01:57
    0
    F = π/4 ρ d² v²

    Explanation:

    Force is mass times acceleration:

    F = ma

    Acceleration is change in velocity over change in time:

    F = m Δv / Δt

    Since there's no rebound, Δv = v.

    F = m v / Δt

    Mass is density times volume:

    F = ρ V v / Δt

    Volume per time is flow rate:

    F = ρ Q v

    Flow rate is velocity times cross sectional area:

    F = ρ (v A) v

    F = ρ A v²

    Area of a circle is pi times radius squared, or pi/4 times diameter squared:

    F = ρ (π/4 d²) v²

    F = π/4 ρ d² v²
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A horizontal jet of water is made to hit a vertical wall with a negligible rebound. If the speed of water from the jet is 'v', the diameter ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers