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2 November, 04:11

You push your textbook 1.5 m along a horizontal tabletop with a horizontal push of 2.4 N while the opposing force of friction is 0.6 N. What is the net work done on the book?

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  1. 2 November, 06:55
    0
    2.7 J

    Explanation:

    Firstly calculate the resultant force ...,

    ; Resultant force = 2.4 - 0.6

    = 1.8 N

    ; Hence net work done = Resultant force * Distance moved by the body

    ; Net work done = 1.8 * 1.5

    ; Net work done = 2.7 J
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