A truck on the freeway originally moving at 6.6 meters/second accelerates uniformly with acceleration a = 2.8 meters/second2 for 7.9 seconds. How far did the truck travel during that time interval?

139.514 metres

Explanation:

Initial velocity of the truck = 6.6 m/s

Acceleration of the truck = 2.8 m/s^2

Time interval = 7.9 s

Therefore we use the formula,

s = ut + 1/2 at^2

*where s (the distance travelled) ... u (the initial velocity) ... t (the time period)

; s = 6.6 (7.9) + 1/2 (2.8) (7.9) ^2

; s = 52.14 + 87.374

The distance moved by the truck = 139.514m