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3 November, 05:29

A truck on the freeway originally moving at 6.6 meters/second accelerates uniformly with acceleration a = 2.8 meters/second2 for 7.9 seconds. How far did the truck travel during that time interval?

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  1. 3 November, 05:57
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    139.514 metres

    Explanation:

    Initial velocity of the truck = 6.6 m/s

    Acceleration of the truck = 2.8 m/s^2

    Time interval = 7.9 s

    Therefore we use the formula,

    s = ut + 1/2 at^2

    *where s (the distance travelled) ... u (the initial velocity) ... t (the time period)

    ; s = 6.6 (7.9) + 1/2 (2.8) (7.9) ^2

    ; s = 52.14 + 87.374

    The distance moved by the truck = 139.514m
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