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15 May, 14:41

You want the current amplitude through a 0.450-mH inductor (part of the circuitry for a radio receiver) to be 1.80 mA when a sinusoidal voltage with amplitude 12.0 V is applied across the inductor. What frequency is required?

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  1. 15 May, 15:41
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    2.36 x 10^6 Hz

    Explanation:

    We know;,

    Iamp = 1.8mA

    L = 0.45mH

    VL = 12V

    VL = IwL

    VL = I x 2π x f x L

    f = VL / (I x 2π x L)

    f = 12 V / (1.8mA x 2π x 0.45mH)

    f = 12 / (1.8x10^-3 x 2π x 0.45 x 10^-3)

    f = 2.36 x 10^6 Hz
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