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31 May, 08:06

Three liquids that will not mix are poured into a cylindrical container. The volumes and densities of the liquids are

0.574 L, 2.50 g/cm3;

0.445 L, 1.04 g/cm3; and

0.498 L, 0.659 g/cm3.

What is the force on the bottom of the container due to these liquids?

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  1. 31 May, 11:36
    0
    Force on the bottom of the container due to liquids is 21.86 N

    Explanation:

    Total force is total weight of liquid.

    Weight = Mass x Acceleration due to gravity

    Liquid 1

    Volume = 0.574 L = 574 cm³

    Density = 2.50 g/cm³

    Mass = 574 x 2.50 = 1435 g = 1.435 kg

    Liquid 2

    Volume = 0.445 L = 445 cm³

    Density = 1.04 g/cm³

    Mass = 445 x 1.04 = 462.8 g = 0.463 kg

    Liquid 3

    Volume = 0.498 L = 498 cm³

    Density = 0.659 g/cm³

    Mass = 498 x 0.659 = 328.18 g = 0.33 kg

    Total mass of liquids = 1.435 + 0.463 + 0.33 = 2.228 kg

    Weight = Mass x Acceleration due to gravity

    Weight = 2.228 x 9.81

    Weight = 2.228 x 9.81 = 21.86 N

    Force on the bottom of the container due to these liquids = 21.86 N
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