Determine the minimum gauge pressure needed in the water pipe leading into a building if water is to come out of a faucet on the twelfth floor, 45 m above that pipe. Express your answer using two significant figures.

P (gauge) = 450 KPa

Explanation:

Given that

h = 45 m

We know that, density of water ρ = 1000 kg/m³

The acceleration due to gravity g = 10 m/s²

As we know that pressure above the atmospheric pressure is known as gauge pressure. And the summation of gauge and atmospheric pressure is known as absolute pressure.

The gauge pressure P (gauge) given as

P (gauge) = ρ g h

Now by putting the values

P (gauge) = ρ g h

P (gauge) = 1000 x 10 x 45 Pa

P (gauge) = 450 KPa