A baseball is thrown directly upward from ground level with a velocity of + 15 m/s. What are the two times when the ball is 10 m above ground level? Take acceleration due to gravity to be - 9.8 m/s^2.

time is 0.5660 s

and time is - 3.62431 s

Explanation:

velocity u = 15 m/s

height s = 10 m

acceleration due to gravity g = - 9.8 m/s²

to find out

time

solution

we will apply here distance equation that is

s = ut - 1/2 * gt² ... 1

here put all these value and get time t

here s is height and g is - 9.8

so

s = ut - 1/2 * gt²

10 = 15t - 1/2 * (-9.8) t²

10 = 15t + 4.9t²

solve it we get t

t = 0.56630 and - 3.62431

so time is 0.5660 s

and time is - 3.62431 s