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12 March, 10:29

a cheetah starting from rest accelerates at a rate of 2.5m/s^2 to reach a speed of 45 m/s. how fare does the cheetah travel

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  1. 12 March, 11:34
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    405 m

    Explanation:

    Given:

    v₀ = 0 m/s

    a = 2.5 m/s²

    v = 45 m/s

    Find: Δx

    v² = v₀² + 2aΔx

    (45 m/s) ² = (0 m/s) ² + 2 (2.5 m/s²) Δx

    Δx = 405 m
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