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29 July, 08:30

In moving out of a dormitory at the end of the semester, a student does 2.17 x 104 J of work. In the process, his internal energy decreases by 5.03 x 104 J. Determine each of the following quantities (including the algebraic sign) : (a) W, (b) U, and (c) Q.

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  1. 29 July, 11:00
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    a. W = 2.17 x 10 ⁴ J

    b. ΔU = - 5.03 x 10⁴ J

    c. Q = 2.86 x 10 ⁻³ J

    Explanation:

    a.

    The student work does 2.17 x 10⁴ J

    So W = 2.17 x 10 ⁴ J

    b.

    The internal energy decreases 5.03 x 10⁴ J

    ΔU = U₁ - U₂

    ΔU = 0 - 5.03 x 10⁴ J = - 5.03 x 10⁴ J

    c.

    The formula heat can use:

    Q = W + ΔU

    Q = 2.17 x 10⁴ J + ( - 5.03 x 10⁴ J)

    Q = 2.86 x 10 ⁻³ J
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