A student has a mass (including clothes and shoes) of 65.0 kg. She drinks a 12 oz. can of soda, with a nutritional energy content of 140 Cal. Assuming that the efficiency of her muscles is 20%, how high can she climb without losing weight?

Conversion: 1 Cal = 1,000 cal = 4,180 J

Question

Physics

Irwin

13 February, 18:27

A student has a mass (including clothes and shoes) of 65.0 kg. She drinks a 12 oz. can of soda, with a nutritional energy content of 140 Cal. Assuming that the efficiency of her muscles is 20%, how high can she climb without losing weight?

Conversion: 1 Cal = 1,000 cal = 4,180 J

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Answers (1)

Know the Answer?

Bradyn Mercer · Answer 1

She can climb 0.92 m without losing weight.

Explanation:

Gravitational potential energy is the energy consisting of the product of mass, gravity and height.

1 cal = 4184 J

140 cal = 585760 J

Energy = 585760 J, m = 65.0 kg = 65000 g, Efficiency = 20 %

GPE = mgh

where m represents the mass

g represents the gravity,

h represents the height.

585760 = 65000 9.8 h

h = 0.92 m.

A student has a mass (including clothes and shoes) of 65.0 kg. She drinks a 12 oz. can of soda, with a nutritional energy content of 140 Cal. Assuming that the efficiency of her muscles is 20%, how high can she climb without losing weight?Conversion: 1 Cal = 1,000 cal = 4,180 J

A student has a mass (including clothes and shoes) of 65.0 kg. She drinks a 12 oz. can of soda, with a nutritional energy content of 140 Cal. Assuming that the efficiency of her muscles is 20%, how high can she climb without losing weight?

Conversion: 1 Cal = 1,000 cal = 4,180 J