a skydiver jumps out of a airplane traveling with a horizontal velocity of 394.3m/s she falls for 3.9 seconds before she opens her parachute how far has she traveled in the horizontal direction in this time

Assume no air resistance before she opens her parachute.

Given in the x direction:

v₀ = 394.3 m/s

a = 0 m/s²

t = 3.9 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (394.3 m/s) (3.9 s) + ½ (0 m/s²) (3.9 s) ²

Δx ≈ 1538 m

Round as needed.