If the gravitational field strength at the top of Mount Everest is 9.772 N/kg, approximately how tall (in feet) is

the mountain?

The height of the Everest mountain is, x = 8514.087 m

Explanation:

Given data,

The gravitational field strength at the top of mount Everest, gₓ = 9.772 m/s²

The formula for gravitational field strength is,

gₓ = GM / (R+x) ²

Where, x is the height from the surface of the Earth

Therefore,

(R+x) ² = GM/gₓ

x = √ (GM/gₓ) - R

Substituting the values,

x = √ (6.67408 x 10⁻¹¹ X 5.972 x 10²⁴ / 9.772) - 6.378 x 10⁶

x = 8514.087 m

Therefore, the height of the Everest mountain is, x = 8514.087 m