To determine the specific heat of an object, a student heats it to 100 degrees C in boiling water. She then places the 110 g object in a 172 g aluminum calorimeter containing 148 g of water. The aluminum and water are initially at a temperature of 19.6 degrees, and are thermally insulated from their surroundings.

If the final temperature is 23.8 degrees, what is the specific heat of the object?

Question

Physics

Denzel Cannon

30 January, 00:29

To determine the specific heat of an object, a student heats it to 100 degrees C in boiling water. She then places the 110 g object in a 172 g aluminum calorimeter containing 148 g of water. The aluminum and water are initially at a temperature of 19.6 degrees, and are thermally insulated from their surroundings.

If the final temperature is 23.8 degrees, what is the specific heat of the object?

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Answers (1)

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Nguyen · Answer 1

Cs=912.6J/kg/K

Explanation:

Sum of Heat gained=sum heat lośs

Definition of terms

Ms=mass of substance 0.11kg

Cs=specific heat capacity of the substance?

Ts = temperature of the substance

Tm = temperature of mixture 28.8°C

Tal = temperature of aluminium19.6°C

Tw=temperature of water 19.6°C

Mal=mass of aluminium 0.172kg

Mw=mass of water 0.148kg

Cw = specific heat capa of water 4200j/kgk

Cal=specific heat capacity of aluminium 903j/kgk

Having gotten all the parameters needed

Ms*Cs * (Ts-Tm) = Mw*Cw * (Tm-Tw) + Mal*Cal * (Tm-Tal)

0.11*Cs * (100-28.8) = 0.148*4200 * (28.8-19.6) + 0.172*903 * (28.8-19.6)

cs= = ((4467267) / (4895))

Cs=912.61Jkg-1K-1