In a fluorescent tube of diameter 3 cm, 3 times 1018 electrons and 0.75 times 1018 positive ions (with a charge of + e) flow through a cross-sectional area each second. What is the current in the tube?

Question

Physics

Abril Hines

25 March, 23:39

In a fluorescent tube of diameter 3 cm, 3 times 1018 electrons and 0.75 times 1018 positive ions (with a charge of + e) flow through a cross-sectional area each second. What is the current in the tube?

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Answers (1)

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Elisabeth Pope · Answer 1

current in the tube is 0.6A

Explanation:

Charged particles move in opposite directions, thus their contributions to total current are additive.

I = (3 * 10¹⁸ + 0.75 * 10¹⁸) * (1.6 * 10⁻¹⁹)

I = 0.6A