Ask Question
23 June, 09:09

A circular curve of highway is designed for traffic moving at 75 km/h. (a) If the radius of the curve is 145 m, what is the correct angle of banking of the road? ° with respect to the horizontal (b) If the curve were not banked, what would be the minimum coefficient of friction between tires and road that would keep traffic from skidding out of the turn when traveling at 75 km/h?

+1
Answers (1)
  1. 23 June, 09:53
    0
    a) 16.97o b) 0.305

    Explanation:

    Using bank angle formula

    Tan (bank angle) = V^2 / (r*g)

    Where V = speed of the traffic = 75Km/hr, converting it to m/s = 75 * 1000m / (3600s) = 20.833m/s, r = radius of the curved path in metres and g = acceleration due to gravity in m/s^2

    Tan (bank angle) = 20.833 ^2 / (145 * 9.81) = 0.305

    Bank angle = tan inverse of (0.305) = 16.97o

    b) Using the formula when the road is unbanked

    Vmax = √coefficient friction * r * 9.81

    V^2 max / (r*g) = coefficient of friction

    Coefficient of friction = 0.305
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A circular curve of highway is designed for traffic moving at 75 km/h. (a) If the radius of the curve is 145 m, what is the correct angle ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers