The front of a 1300 kg car is designed to absorb the shock of a collision by having a "crumple zone" in which the front 1.20 m of the car collapses in absorbing the shock of a collision. (a) If a car traveling 29.0 m/s stops uniformly in 1.20 m, how long does the collision last

The collision last 0.83 s

Explanation:

Using the equation of motion,

S = (v+u) t/2 ... Equation 1

making t the subject of the equation,

t = 2S / (v+u) ... Equation 2

Where S = distance, v = final velocity, u = initial velocity, t = time

Given: v = 0 m/s, u = 29.0 m/s, S = 1.20 m,

Substituting these values into equation 2

t = 2 (1.2) / (29+0)

t = 2.4/29

t = 0.83 sec.

Thus the collision last 0.83 s