What is the rate at which work is done in lifting a 35 kg object vertically at a constant speed of 5 m/s?

1 1700 W

2 340 W

3 180 W

4 7.0 W

1,700 W

Explanation:

The rate at which work is done is also the power dissipated in lifting the object at that constant speed.

Power = force x speed

= mg x v

= (35 x 9.8) x 5

= 1715 W

This is approximately 1,700 W

Therefore, the the rate at which work is done in lifting the object vertically at a constant speed of 5 m/s is 1,700 W.

1700 W

Explanation:

Power = work / time

Power = force * distance / time

Power = force * velocity

P = (35 kg) (9.8 m/s²) (5 m/s)

P = 1700 W