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27 August, 12:41

Calculate the magnetic field strength needed on a  170-turn square loop  22  cm on a side to create a maximum torque of  295  N·m if the loop is carrying  20  A.

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  1. 27 August, 12:46
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    B = 1.823 T.

    Explanation:

    Given,

    Number of turns, N = 170 turn

    Side of square loop, L = 22 cm

    Maximum torque, τ = 295 N. m

    Current on the loop, I = 20 A

    Magnetic strength = ?

    Torque = N BIA

    300 = 170 x B x 20 x 0.22²

    300 = 164.56 B

    B = 1.823 T.

    Hence, the magnetic field strength is equal to B = 1.823 T.
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