Ask Question
26 March, 19:30

To practice Problem-Solving Strategy 21.1 Conservation of energy in charge interactions. An alpha particle (α), which is the same as a helium-4 nucleus, is momentarily at rest in a region of space occupied by an electric field. The particle then begins to move. Find the speed of the alpha particle after it has moved through a potential difference of - 3.45*10-3 V. The charge and the mass of an alpha particle are qα = 3.20*10-19 C and mα = 6.68*10-27 kg, respectively.

+3
Answers (1)
  1. 26 March, 22:52
    0
    kinetic energy of alpha particle

    = Q X V (Q is charge on the particle and V is potential difference)

    = 3.2 x 10⁻¹⁹ x 3.45 x 10⁻³

    = 11.04 x 10⁻²² J

    1/2 m v² = 11.04 x 10⁻²²

    1/2 x 6.68 x 10⁻²⁷ x v² = 11.04 x 10⁻²²

    v² = 3.305 x 10⁵

    v = 5.75 x 10² m / s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “To practice Problem-Solving Strategy 21.1 Conservation of energy in charge interactions. An alpha particle (α), which is the same as a ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers