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25 June, 22:21

calculate the final centigrade temperature required to change 20 litres of gas at 120 degree Celsius and 1 atmosphere to 25 litres at 2 atmosphere

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  1. 25 June, 22:46
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    pv=nRT

    1*20 = (273+120) * 0.0082*N

    2*25 = (273+T) * 0.082*N

    (273+T) = 1965/2

    T=609.5
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