If i = 1.70 A of current flows through the loop and the loop experiences a torque of magnitude 0.0760 N ⋅ m, what are the lengths of the sides s of the square loop, in centimeters?

Length of the sides of the square loop is given by

s = √[ (τ) / (NIB sin θ) ]

Explanation:

The torque, τ, experienced by a square loop of area, A, with N number of turns around the loop and current of I flowing in the wire, with a magnetic field presence, B, and the plane of the loop tilted at angle θ to the x-axis, is given by

τ = (N) (I) (A) (B) sin θ

If everything else is given, the length of a side of the square loop, s, can be obtained from its Area, A.

A = s²

τ = (N) (I) (A) (B) sin θ

A = (τ) / (NIB sin θ)

s² = (τ) / (NIB sin θ)

s = √[ (τ) / (NIB sin θ) ]

In this question, τ = 0.076 N. m, I = 1.70 A

But we still need the following to obtain a numerical value for the length of a side of the square loop.

N = number of turnsof wire around the loop

B = magnetic field strength

θ = angle to which the plane of the loop is tilted, measured with respect to the x-axis.