Ask Question
17 November, 04:53

A projectile is fired straight upward with an initial veloc - ity of 100 m=s from the top of a building 20 m high and falls to the ground at the base of the building. Find (a) its maximum height above the ground; (b) when it passes the top of the building; (c) its total time in the air.

+4
Answers (1)
  1. 17 November, 06:21
    0
    The answer to your question is:

    a) h max = 529.7 m

    b) t = 20.4 s

    c) t = 20.6 s

    Explanation:

    a) h max = - (vo) ² / 2g

    = 100² / 2 (9.81)

    = 10000 / 19.62

    = 509.7 m

    total height = 509.7 + 20 = 529.7 m

    b)

    h = gt² / 2

    t = √ 2h / g

    t = √ 2 (509.7) / 9.81

    t = √ 103.91

    t = 10.19 s

    total time = 2 x t = 2 x 10.19 = 20.4 s

    c)

    h = vot + 1/2gt²

    20 = 100t + 1/2 (9.91) t²

    4.9t² + 100 t - 20 = 0 quadratic equation

    t = 0.19 s

    Total time = 0.19 + 20.4 = 20.6 s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A projectile is fired straight upward with an initial veloc - ity of 100 m=s from the top of a building 20 m high and falls to the ground ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers