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5 July, 13:20

When its 75 kW (100 hp) engine is generating full power, a small single-engine airplane with mass 700 kg gains altitude at a rate of 2.5 m/s (150 m/min, or 500 ft/min). What fraction of the engine power is being used to make the airplane climb

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  1. 5 July, 15:00
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    343/1500

    Explanation:

    Power: This can be defined as the product force and velocity. The S. I unit of power is Watt (w).

    From the question,

    P' = mg*v ... Equation 1

    Where P' = power used to gain an altitude, m = mass of the engine, g = acceleration due to gravity of the engine, v = velocity of the engine.

    Given: m = 700 kg, v = 2.5 m/s, g = 9.8 m/s²

    Substitute into equation 1

    P' = 700 (2.5) (9.8)

    P' = 17150 W.

    If the full power generated by the engine = 75000 W

    The fraction of the engine power used to make the climb = 17150/75000

    = 343/1500
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