What is the hang time when the person moves 6 m horizontally during a 1.25 m high jump?

1 sec

Explanation:

Horizontal distance (x) = 6m

Vertical distance (y) = 1.25m

Hang time is the duration the object is in the air before it reaches maximum height.

The time of free fall is given by

t = √2y/g

g = acceleration due to gravity

t = √ (2*1.25) / 9.8

t = √2.5/9.8

t = 0.5secs

Hang time = 2*0.5

= 1 sec