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4 February, 16:53

Caculate the heat realeased as a 25.0 g gas sample condenses if the heat vaporation is 2000 j/g

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  1. 4 February, 19:23
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    The amount of heat required to change 25 grams of water into steam is 50,000 joules or 11,950 calories.

    Explanation:

    Heat of vaporization of water = 2000J/g = 478 cal/g

    You can solve this problem using either joules or calories for heat.

    Part I

    Use the formula q = m·ΔHv

    where

    q = heat energy

    m = mass

    ΔHv = heat of vaporization

    q = (25 g) x (2000J/g)

    q = 50,000 J

    Part II

    q = m·ΔHf

    q = (25 g) x (478 cal/g)

    q = 11,950 cal

    Answer

    The amount of heat required to change 25 grams of water into steam is 50,000 joules or 11,950 calories.
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