A cab driver heads south with a steady speed of v1 = 22.0 m/s for t1 = 3.00 min, then makes a right turn and travels at v2 = 25.0 m/s for t2 = 2.40 min, and then drives northwest at v3 = 30.0 m/s for t3 = 1.00 min. For this 6.40-min trip, calculate the following. Assume + x is in the eastward direction.

Question

Physics

Yoselin Hawkins

17 September, 23:11

A cab driver heads south with a steady speed of v1 = 22.0 m/s for t1 = 3.00 min, then makes a right turn and travels at v2 = 25.0 m/s for t2 = 2.40 min, and then drives northwest at v3 = 30.0 m/s for t3 = 1.00 min. For this 6.40-min trip, calculate the following. Assume + x is in the eastward direction.

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Answers (1)

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Happyt · Answer 1

Answer:3600m

Explanation:

Distance towards south

Distance = speed * time

= 22m/s * 3*60s

(Recall 1m = 60s)

Distance towards south 3960m

Distance Eastward direction (+x)

Distance = speed * time

= 24m/s * 2.4 * 60s

= 3600m

Distance Northwest direction

Distance = 30m/s * 1 * 60s

=1800m