Ask Question
27 July, 11:16

1) A force of 20 Newton acts on a bar having a cross sectional area of 0.8m^2 and length 10cm. calculate the stress developed in the bar

+4
Answers (1)
  1. 27 July, 12:23
    0
    Answer:25N/M^2

    Explanation:

    Force=20N Area=0.8M^2

    Stress=force/area

    Stress=20/0.8

    Stress=25N/M^2
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “1) A force of 20 Newton acts on a bar having a cross sectional area of 0.8m^2 and length 10cm. calculate the stress developed in the bar ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers