Ask Question
18 September, 14:32

You throw a ball straight upward. As it leaves your hand, its speed is 15 m/s. (a) How much time does it take for the ball to reach the top of its trajectory? Start from a fundamental principle and show all your work.

+1
Answers (2)
  1. 18 September, 15:53
    0
    the ball takes 1.53 s to reach the top of its trajectory.

    Explanation:

    given information:

    the speed, v = - 15 m/s (moving upward)

    (a) How much time does it take for the ball to reach the top of its trajectory?

    we know that the speed for the vertical motion is

    v = v₀ - gt, v₀ = 0

    where

    v = speed (m/s)

    g = gravitational force (9.8 m/s²)

    t = time (s)

    thus

    v = - gt

    -15 = - 9.8 t

    t = 15/9.8

    = 1.53 s

    so, the time that is needed by the ball to reach the top its trajectory is 1.53 s
  2. 18 September, 16:28
    0
    The ball takes 1.53 seconds to reach its top trajectory

    Explanation:

    The velocity of the ball will keep pushing it upwards until the velocity becomes zero. Therefore, the ball will reach the top of its trajectory when velocity i. e. V=0,

    Fundamental principal of velocity is V = Vo + g*t

    where, V=0

    Vo = 15 m/s

    g = - 9.8 m/s^2 (since ball is going upwards against the gravity)

    t = ?

    0 = 15 + (-9.8 * t)

    -15 = - 9.8t

    -15 / - 9.8 = t

    t = 1.53 Seconds

    The ball takes 1.53 seconds to reach its top trajectory
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “You throw a ball straight upward. As it leaves your hand, its speed is 15 m/s. (a) How much time does it take for the ball to reach the top ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers