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30 December, 09:44

A girl throws a ball of mass 0.80 kg against a wall. The ball strikes the wall horizontally with a speed of 25 m/s, and it bounces back with this same speed. The ball is in contact with the wall 0.050 s. What is the magnitude of the average force exerted on the wall by the ball

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  1. 30 December, 13:08
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    F = 800N

    the magnitude of the average force exerted on the wall by the ball is 800N

    Explanation:

    Applying the impulse-momentum equation;

    Impulse = change in momentum

    Ft = m∆v

    F = (m∆v) / t

    Where;

    F = force

    t = time

    m = mass

    ∆v = v2 - v1 = change in velocity

    Given;

    m = 0.80 kg

    t = 0.050 s

    The ball strikes the wall horizontally with a speed of 25 m/s, and it bounces back with this same speed.

    v2 = 25 m/s

    v1 = - 25 m/s

    ∆v = v2 - v1 = 25 - (-25) m/s = 25 + 25 = 50 m/s

    Substituting the values;

    F = (m∆v) / t

    F = (0.80*50) / 0.05

    F = 800N

    the magnitude of the average force exerted on the wall by the ball is 800N
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