An electron experiences a magnetic force of magnitude 4.60 x 10^-15 N when moving at an angle of 60.0° with respect to a magnetic field of magnitude 3.50 x 10^-3 T. Find the speed of the electron.

9.49 * 10⁶ m/s

Explanation:

Data provided in the question:

Magnitude of Magnetic force, F = 4.60 * 10⁻¹⁵ N

Angle, θ = 60°

Magnitude of magnetic field, B = 3.50 * 10⁻³ T

Now,

we know

F = qVBsin (θ)

here,

q is the charge of electron = 1.6 * 10⁻¹⁹ V

V is the speed of electron

Therefore,

4.60 * 10⁻¹⁵ = (1.6 * 10⁻¹⁹) * V * (3.50 * 10⁻³) * sin (60°)

or

V = 9.49 * 10⁶ m/s