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30 July, 00:00

A sample of gas has a volume of 42 L at a pressure of 200 kPa and a temperature of 30^ * C. What would be the volume, if the pressure were increased to 250 kPa and the temperature were decreased to 5^ * C?

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  1. 30 July, 01:24
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    30 L

    Explanation:

    Ideal gas law:

    PV = nRT

    Rearranging:

    PV / T = nR

    Since n and R are constant:

    P₁ V₁ / T₁ = P₂ V₂ / T₂

    Plugging in values and solving:

    (200 kPa) (42 L) / (30 + 273.15 K) = (250 kPa) V / (5 + 273.15 K)

    V = 30.8 L

    Rounded to one significant figure, the new volume is 30 L.
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