If the pressure of the gas is doubled while the volume is held constant, what happens to its temperature? [Section 10.4] If the pressure of the gas is doubled while the volume is held constant, what happens to its temperature? [Section 10.4] That is, if P is doubled, T increases by a factor of two. That is, if P is doubled, T increases by a factor of four. That is, if P is doubled, T decreases by a factor of three. That is, if P is doubled, T decreases by a factor of two. That is, if P is doubled, T increases by a factor of three. That is, if P is doubled, T increases by a factor of four.

That is, if P is doubled, T increases by a factor of two.

Explanation:

For an ideal gas, we can write the following equation:

P*V = n * R * T

If we take an initial state, with parameters P₁, V₁, T₁, we can write the equation as follows:

P₁ * V₁ = n * R * T₁ (1)

Now, we are told that the same mass of gas, changes its state, doubling its pressure, while the volumen is held constant.

We can use the same equation as above, replacing P₁, V₁, T₁ by the new values P₂, V₂, T₂, where P₂ = 2 * P₁, and V₂ = V₁, as follows:

2 * P₁ * V₁ = n * R * T₂ (2)

Dividing both sides in (2) and (1), we get:

T₂ / T₁ = 2

This means that if the pressure is doubled, temperature increases by a factor of two.