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10 March, 00:16

The speed of sound in room temperature (20°C) air is 343 m/s; in room temperature helium, it is 1010 m/s. The fundamental frequency of an open-closed tube is 315 Hz when the tube is filled with air. What is the fundamental frequency if the air is replaced with helium?

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  1. 10 March, 02:25
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    Answer: f = 927.55Hz

    Explanation: Since the the tube is open-closed, the length of air and the wavelength of sound passing through the tube is given below

    L = λ/4 where λ = wavelength.

    speed of sound in air = v = 343m/s.

    fundamental frequency of open closed tube = 315Hz

    λ = 4L.

    v = fλ

    343 = 315 * 4L

    343 = 1260 * L

    L = 343 / 1260

    L = 0.27m

    In the same tube of length L = 0.27m but different medium (helium), the speed of sound is 1010m/s.

    The length of tube and wavelength are related by the formulae below

    L = λ/4, λ=4L

    λ = 4 * 0.27

    λ = 1.087m.

    v = fλ

    1010 = f * 1.087

    f = 1010/1.807

    f = 927.55Hz
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